IPWorks OpenPGP 2020 Kotlin Edition

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DecodeFromFile Method

Decodes from file.

Syntax

public fun decodeFromFile()

Remarks

This method decodes the data file given in Message and optionally MessageHeaders and fills out the Parts collection for each decoded part.

Example (Decoding From File)


MIMEControl.Message = "C:\filename.txt"
MIMEControl.DecodeFromFile

Here, C:\filename.txt must contain the MIME headers and body. If not, the MessageHeaders property must also be set to the appropriate MIME headers.

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IPWorks OpenPGP 2020 Kotlin Edition - Version 20.0 [Build 7941]