SendFile Method

Sends a file to the specified client.

Syntax

public void SendFile(string connectionId, string clientSFIDCode, string fileName, string virtualFileName);
Public Sub SendFile(ByVal ConnectionId As String, ByVal ClientSFIDCode As String, ByVal FileName As String, ByVal VirtualFileName As String)

Remarks

This method sends a file to the client specified by the ConnectionId parameter.

After the ReadyToSend event fires or when the ReadyToSend field is true, this method can be used to send a file to the connected client specified by the ConnectionId parameter.

The ClientSFIDCode corresponds to the destination.

FileName must be the full path to the file which will be sent.

VirtualFileName may be specified to indicate the name of the file that the client will see when receiving the file.

If UploadStream is set, pass empty string as the value for the FileName parameter.

When this method is called, the component will fire the StartTransfer, Transfer, and EndTransfer events that can be monitored to check the status of the send. The SendFile method will not return until either the transfer is complete or an error was encountered.

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IPWorks EDI 2020 .NET Edition - Version 20.0 [Build 8203]